Chemistry - Mole Concept Question with Solution | TestHub

No. of moles of oxygen in $0.16\mathrm{g}$ of oxygen molecule $=\frac{0.16\mathrm{g}}{32\mathrm{g}/\mathrm{mol}}=0.005\mathrm{mole}$ $2{\mathrm{NaClO}}_3\stackrel{\Delta }{⟶}2\mathrm{NaCl}+3{\mathrm{O}}_2$ According to the reaction, $3$ moles of ${\mathrm{O}}_2=2$ moles of $\mathrm{NaCl}$ $=2$ moles of $\mathrm{AgCl}$ Molar mass of $\mathrm{AgCl}=143.5\mathrm{g}/\mathrm{mol}$ $0.005$ moles of ${\mathrm{O}}_2$ will ppt. $=0.005\times \frac{2}{3}$ moles $\mathrm{AgCl}$ $=0.0033\text{ moles of }\mathrm{AgCl}$ $\therefore$ Mass of $\mathrm{AgCl}$ (in $\mathrm{g}$) obtained will be $=143.5\mathrm{g}/\mathrm{mol}\times 0.0033$ moles $=0.48\mathrm{g}$.