The number of atoms in ' A g m ' of an element (molecular formula = X n ) is 1.8 × 1 0 24 , where ' A ' is molecular mass of the element and ' n ' is some integer. The value of ' n ' is (Take : Avogadro's number N A = 6 × 10 23 )

A gm (molecular mass) contains 6 × 1 0 23 molecules ∴ n × 6 × 1 0 23 = 1.8 × 1 0 24 n = 3

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The number of atoms in ' $A g m$ ' of an element (molecular formula $= X_{n}$ ) is $1.8 \times 1 0^{24}$ , where ' A ' is molecular mass of the element and ' n ' is some integer. The value of ' n ' is

(Take : Avogadro's number N_A = 6 × 10²³ )

Options:

Answer:

Solution:

A gm (molecular mass) contains $6 \times 1 0^{23}$ molecules

$∴ n \times 6 \times 1 0^{23} = 1.8 \times 1 0^{24} n = 3$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Atomic mass/Average Atomic Mass/Average Molecular Mass

⏱ 2mℹ️ Source: QB

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