Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediummultiple choice

Calculate the amount of lime that can be produced by heating 100 g of $90%$ pure limestone

Answer:

A, C

Solution:

$C a C O_{3} ⟶ C a O + C O_{2}$

$100 g 56 g$

$100 g C a C O_{3} = 56 g C a O$

Therefore, $90 g C a C O_{3} = \frac{90}{100} \times 56 g C a O$ , which is $50.4 g C a O$ .

Number of moles of $C a O = \frac{50.4}{56} = 0.9$ .

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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