The number of N atoms in 681 g of C 7 H 5 N 3 O 6 is x × 10 21 . The value of x is N A = 6 . 02 × 10 23 mol - 1 (Nearest Integer)

Given mass of compounds = 681 g Molar mass of C 7 H 5 N 3 O 6 = 12 × 7 + 5 × 1 + 14 × 3 + 6 × 16 = 84 + 5 + 42 + 96 = 227 Number of moles of compound = 681 227 = 3 moles Number of moles of N = 3 × number of moles of compound = 3 × 3 = 9 moles Number of atoms of N = 9 × 6 . 02 × 10 23 = 5418 × 10 21 So x = 5418

Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedMedium2 minPYQ_2022

ChemistryMediumassertion reason

The number of $N$ atoms in $681 g$ of $C_{7} H_{5} N_{3} O_{6}$ is $x \times 10^{21}$ . The value of $x$ is $(N_{A} = 6.02 \times 10^{23} {mol}^{- 1})$ (Nearest Integer)

Answer:

5418

Solution:

Given mass of compounds $= 681 g$

Molar mass of $C_{7} H_{5} N_{3} O_{6} = 12 \times 7 + 5 \times 1 + 14 \times 3 + 6 \times 16$

$= 84 + 5 + 42 + 96$

$= 227$

Number of moles of compound $= \frac{681}{227} = 3$ moles

Number of moles of $N = 3 \times$ number of moles of compound

$= 3 \times 3 = 9$ moles

Number of atoms of N $= 9 \times 6.02 \times 10^{23}$

$= 5418 \times 10^{21}$

So $x = 5418$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2022

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