A mixed solution of potassium hydroxide and sodium carbonate required 15 mL of a N /20 HCl solution when titrated with phenolphthalein as an indicator. But the same amount of the solution when titrate

Question

A mixed solution of potassium hydroxide and sodium carbonate required 15 mL of a N /20 HCl solution when titrated with phenolphthalein as an indicator. But the same amount of the solution when titrated with methyl orange as an indicator required 25 mL of the same acid. Calculate the amount of KOH present in the solution.

TestHub · Accepted Answer

With phenolphthalein, n K O H ​ + n N a 2 ​ C O 3 ​ ​ = 0.75 × 1 0 − 3 (1) With methyl orange, n K O H ​ + n N a 2 ​ C O 3 ​ ​ = 1.25 × 1 0 − 3 (2) From (1) and (2), n K O H ​ = 0.25 × 1 0 − 3 . Amount of KOH = 0.25 × 1 0 − 3 × 56 = 0.014 g .

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