Chemistry - Mole Concept Question with Solution | TestHub

\begin{array}{ll:cccl} & \mathrm{C} & \mathrm{Cl} & \mathrm{H} & \mathrm{O} & \\ \text { %mass } & 14.5 & 64.46 & 1.8 & 19.24\end{array} Molar ratio $\frac{14.5}{12}\frac{64.46}{35.5}\frac{1.8}{1}\frac{19.24}{16}$ $\begin{array}{rl}& \begin{array}{ccccc}& 1.2& 1.8& 1.8& 1.2\\ \text{ Minimum }& 2& 3& 3& 2\end{array}\\ & \text{ integral ratio }\end{array}$ $\begin{array}{rl}& \text{ Empiricial formula }={\mathrm{C}}_2{\mathrm{H}}_3{\mathrm{Cl}}_3{\mathrm{O}}_2\\ & \text{ Mass }=165.5\\ & \text{ Mass }=1655\times 10^{-1}\end{array}$