Chemistry - Mole Concept Question with Solution | TestHub
A mixture of and butene was collected in a Eudiometer tube. Then, 80 ml of oxygen were also introduced. The resulting mixture of all the gases was exploded. After cooling resulting gaseous mixture passes through KOH solution which caused a contraction of 32 ml and 16 ml of oxygen alone were left behind.
Calculate contraction in volume (in ml) (after explosion and cooling of resulting mixture).
Options:
Answer:
Solution:
Let butene = mL and H₂ = mL.
For butene: C₄H₈ + 6O₂ → 4CO₂ + 4H₂O
KOH contraction = CO₂ = 32 mL , so mL.
O₂ consumed by butene = mL. Remaining O₂ = 16 mL, so total O₂ consumed = mL.
O₂ consumed by H₂ = mL H₂ volume = 32 mL.
Initial mixture volume = H₂ + C₄H₈ = mL.
After cooling, final gas = CO₂ (32 mL) + O₂ (16 mL) = 48 mL.
Total initial gas after adding O₂ = mL.
Contraction = mL.
Correct Answer: (C) 72 mL
