The number of atoms in 8 g of sodium is x × 10 23 . The value of x is _____ . (Nearest integer) Given : N A = 6 . 02 × 10 23 mol - 1 Atomic mass of Na = 23 . 0 u ]

Number of mole of sodium = 8 23 Number of sodium atom = 8 23 × 6 × 10 23 = 2 . 08 × 10 23

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ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2021

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The number of atoms in $8 g$ of sodium is $x \times 10^{23} .$ The value of $x$ is _____ . (Nearest integer)

$[Given : N_{A} = 6.02 \times 10^{23} {mol}^{- 1} Atomic mass of Na = 23.0 u]$

Answer:

Solution:

Number of mole of sodium $= [\frac{8}{23}]$

Number of sodium atom $= [\frac{8}{23}] \times 6 \times 10^{23} = 2.08 \times 10^{23}$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2021

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