Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

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If 0.50 mole of $B a C l_{2}$ is mixed with 0.20 mol of $N a_{3} P O_{4}$ , the maximum number of moles of $B a_{3} (P O_{4})_{2}$ that can be formed is

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Answer:

Solution:

$\underset{0.5}{3 {BaCl}_{2}} + \underset{0.2}{2 {Na}_{3} {PO}_{4}} \to {Ba}_{3} {({PO}_{4})}_{2} + 6 NaCl$
Here Limiting reagent is $N a_{3} P O_{4}$
As 2 mole of $N a_{3} P O_{4}$ gives = 1 mol of $B a_{3} (P O_{4})_{2}$ .
So (0.2 mol) of $N a_{3} P O_{4}$ gives = 0.1 mol of $B a_{3} (P O_{4})_{2}$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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