Chemistry - Mole Concept Question with Solution | TestHub

The mass of ${\mathrm{N}}_2{\mathrm{F}}_4$ obtained by reaction of 2.0 gm of ${\mathrm{NH}}_3$ and 80 gm of ${\mathrm{F}}_2$ is 3.56 gm . The percentage yield of reaction is [ $\mathrm{F}=19$ ]

$N{H}_3+F_2\to N_2{F}_4+HF(\text{not balanced)}$