Chemistry - Mole Concept Question with Solution | TestHub

$\text{17}\text{.0\%}$solution of${\text{CH}}_{\text{3}}\text{COONa}$means that$\text{100}\text{g}$solution contain$\text{17}\text{g}$of${\text{CH}}_{\text{3}}\text{COONa}$.
Moles of${\text{CH}}_{\text{3}}\text{COONa}\text{=}\frac{\text{17}\text{g}}{\text{82}\text{.0}\text{g}{\text{mol}}^{-\text{1}}}\text{=}\frac{\text{17}}{\text{82}\text{.0}}\text{mol}$
Volume of$\text{100}\text{g}$solution$=\frac{\text{Mass of solution}}{\text{Density of solution}}$
$\text{=}\frac{\text{100}\text{g}}{\text{1}\text{.09}\text{g}{\text{mol}}^{-\text{1}}}\text{=}\frac{\text{100}}{\text{1}\text{.09}}\text{mL}$
So molarity of solution$\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Liter}\text{of}\text{soln}\text{.}}$
$\text{=}\frac{\frac{\text{17}}{\text{82}\text{.0}}\text{mol}}{\left(\frac{\text{100}}{\text{1}\text{.09}}\right){\text{×10}}^{-\text{3}}\text{L}}$
$\text{=}\text{2}\text{.259}\text{M}\text{=}\text{2}\text{.26}\text{M}$