Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasynumerical

What mass in miligram ofCaCO3is required to react completely with 25 ml of 0.75 M HCl according to the reactionCaCO3(s)+2HCl(a)CaCl2(a)+CO2(g)+H2O(l)?

Answer:
937.50
Solution:

Given
CaCO 3 (s)+2HCl(aq) CaCl 2 (aq)+ CO 2 (g)+ H 2 O(l)
Moles present in 25 ml of 0.75 M HCl=0.751000×25
=0.01875moles
Since 2 moles react completely with 1mole CaCO 3 =100g
0.01875 moles react completely with CaCO 3 = 100 2 ×0.01875
0.9375g=937.5mg

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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