Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedMedium2 minPYQ_2020
ChemistryMediumnumerical

What mass in miligram ofCaCO3is required to react completely with 25 ml of 0.75 M HCl according to the reactionCaCO3(s)+2HCl(a)→CaCl2(a)+CO2(g)+H2O(l)?

Answer:
937.50
Solution:

Given
CaCO 3 (s) + 2HCl (aq) →  CaCl 2 (aq) +  CO 2 (g) +  H 2 O (l)
Moles present in 25 ml of 0.75 M HCl=0.751000×25
=0.01875moles
Since 2 moles react completely with 1 mole  CaCO 3  = 100 g
0.01875 moles react completely with CaCO 3 = 100 2 ×0.01875
0.9375 g=937.5 mg

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: PYQ_2020

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