Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

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How many ml of aqueous solution of $KMnO_{4}$ containing 158 g litre $^{- 1}$ must be used for complete conversion of 83 g of KI to $I_{2}$ in the presence of $H_{2} SO_{4}$ ?

Options:

Answer:

Solution:

Equivalents of KMnO₄ = Equivalents of KI

$\frac{V}{1000} \times \frac{158 \times 5}{158} = \frac{83 \times 1}{166}$

(where $V$ is the volume of KMnO₄ used in ml)

On solving, $V = 100$ ml.

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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