TestHub
TestHub

Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedMedium2 minQB
ChemistryMediumnumerical
Passage / Comprehension

According to Avogadro’s law, equal numbers of moles of gases occupy the same volume at identical conditions of temperature and pressure. Even if we have a mixture of non-reacting gases, Avogadro’s law is still obeyed by assuming the mixture as a new gas.

Now, let us assume air to consist of 80% by volume of Nitrogen (N₂) and 20% by volume of Oxygen (O₂). If air is taken at 1 atm, 273 K, then its 1 mol would occupy 22.4 L. 1 mol of air would contain 0.8 mol of N₂ and 0.2 mol of O₂. Hence, the mole fractions of N₂ and O₂ are given by:

 

,

Density (in g/L) of air at is :

 

Answer:
1.28
Solution:

Density of air at NTP

1 mole of air mole mole

volume.

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed
2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...