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Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

How many litres of $C l_{2}$ at STP will be liberated by the oxidation of NaCl with 10 g $K M n O_{4}$ ?

Options:

Answer:

Solution:

Meq. of $C l_{2} = M e q .$ of $K M n O_{4}$
$\frac{w}{71 / 2} \times 1000 = \frac{10}{31.6} \times 1000$
So $w_{C l_{2}} = 11.23$ g
So $V_{C l_{2}} = \frac{22.4 \times 11.23}{71} = 3.54$ litre.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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