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Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediumsingle choice

' $y$ ' ml of ' $y$ ' volume $H_{2} O_{2}$ solution completely reacts with ' $x$ ' ml of ' $y$ ' $M KMnO_{4}$ solution in acidic medium. The value of $x / y$ is

Options:

Answer:

Solution:

$H_{2} O_{2} + KMnO_{4} H^{+} Mn^{+ 2} + O_{2}$

Milli-equivalents of H₂O₂ = Milli-equivalents of KMnO₄

$N_{H_{2} O_{2}} V_{H_{2} O_{2}} = N_{K M n O_{4}} V_{K M n O_{4}}$ where volume is in ml.

$\frac{y}{5.6} \times y = y \times 5 \times x$ (Vol. strength = 5.6 N)

$\frac{x}{y} = \frac{1}{5.6 \times 5} = 0.036$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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