Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Calculate normality, molarity and molality of the solution containing 22% (w/w) salt $A l_{2} (S O_{4})_{3} \{d = 1.253 g m / m l\}$ by weight is

Options:

Answer:

Solution:

Normality $= \frac{w / w % \times 10 \times d}{E_{2}}$ $= \frac{22 \times 10 \times 1.253}{\frac{342}{6}} = 4.83 N$

Molarity $= \frac{w / w % \times 10 \times d}{M_{2}} = \frac{22 \times 10 \times 1.253}{342} = 0.805 M$

$E_{2} =$ eq.mass of solute

$M_{2} =$ molar ass of solute

$Molality = \frac{(w / w %) \times 1000}{M_{2} (100 - w / w %)}$

Molality $= \frac{22 \times 1000}{342 (100 - 22)} = 0.825 m$

Stream:NTA_ABHYASSubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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