Chemistry - Mole Concept Question with Solution | TestHub

Normality $=\frac{\mathrm{w}/\mathrm{w} \mathrm{\%}\times \text{10}\times \mathrm{d}}{{\mathrm{E}}_2}$ $=\frac{\text{22}\times \text{10}\times \text{1.253}}{\frac{\text{342}}{6}}=\text{4.83 }\mathrm{N}$

Molarity $=\frac{\mathrm{w}/\mathrm{w} \mathrm{\%}\times \text{10}\times \mathrm{d}}{{\mathrm{M}}_2}=\frac{\text{22}\times \text{10}\times \text{1.253}}{\text{342}}=\text{0.805 }\mathrm{M}$

${\mathrm{E}}_2=$eq.mass of solute

${\mathrm{M}}_2=$molar ass of solute

$\mathrm{Molality} =\frac{\left(\mathrm{w}/\mathrm{w}\%\right)\times 1000}{{\mathrm{M}}_2\left(100-\mathrm{w}/\mathrm{w}\%\right)}$

Molality $=\frac{\text{22}\times \text{1000}}{\text{342}(\text{100}-\text{22})}=\text{0.825 }\mathrm{m}$