Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

ChemistryMediumsingle choice

The total number of protons in 10 g of calcium carbonate is $(NA = 6.023 \times 1 0^{23})$

Answer:

Solution:

No. of protons in : $Ca = 20, C = 6, O = 8$

$100 g CaCO_{3}$ has $= 20 + 6 + (3 \times 8) = 50$ mole protons

$10 g CaCO_{3}$ has $= \frac{50}{100} \times 10 = 5$ mole protons

No. of protons $= 5 \times 6.022 \times 1 0^{23} = 3.011 \times 1 0^{24}$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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