KClO 3 on heating decomposes in two modes 4 K Cl O 3 ⟶ 3 K Cl O 4 + K Cl 2 K Cl O 3 ⟶ 2 K Cl + 3 O 2 If one mole of K Cl O 3 yields on heating a residue in which the mole fraction of K Cl

Question

KClO 3 ​ on heating decomposes in two modes 4 K Cl O 3 ​ ⟶ 3 K Cl O 4 ​ + K Cl 2 K Cl O 3 ​ ⟶ 2 K Cl + 3 O 2 ​ If one mole of K Cl O 3 ​ yields on heating a residue in which the mole fraction of K Cl O 4 ​ is 0.25 , how many moles of O 2 ​ are evolved?

TestHub · Accepted Answer

n ( K Cl O 3 ​ ) = 0.25 × 3 4 ​ (in first reaction) n ( K Cl O 3 ​ ) decomposing in second reaction = ( 1 − 0.25 × 3 4 ​ ) . Thus, n ( O 2 ​ ) = ( 1 − 0.25 × 3 4 ​ ) × 2 3 ​ = 1 .

Chemistry - Mole Concept Question with Solution | TestHub

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