Chemistry - Mole Concept Question with Solution | TestHub

$\text{R}={\text{R}}_0{\left(\text{A}\right)}^{\frac{1}{3}}$
R = Radius of nucleus
R = 5.6 Fermi =$5.6\times 10^{-13}$cm
${\mathrm{A}}^{\frac{1}{3}}=\frac{\mathrm{R}}{{\mathrm{R}}_0}=\frac{5.6\times 10^{-13}}{1.4\times 10^{-13}}=4$
So A = 64.