Chemistry - Mole Concept Question with Solution | TestHub

Equivalents of oxalic acid in 250 mL= $\frac{6.3\times 2}{126}=0.1$

Equivalents of oxalic acid in 10 mL =$\frac{0.1}{250}\times 10=\frac{1}{250}$

Equivalents of NaOH = $\frac{0.1\times V_{mL}}{1000}$

Therefore,

$\frac{0.1\times V}{1000}=\frac{1}{250}$

$V=40mL$