Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptMiscellaneous/MixedEasy2 minPYQ_2012

ChemistryEasysingle choice

The weight of oxalic acid that will be required to prepare a $1000 mL (N /20)$ solution is

Answer:

Solution:

$w = \frac{NE V}{1000} = \frac{1}{20} \times \frac{63 \times 1000}{1000} = \frac{63}{20} g$

Stream:WBJEESubject:ChemistryTopic:Mole ConceptSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2012

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