Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleMedium2 minQB

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A sample of $NaClO_{3}$ is converted by heat to NaCl with a loss of 0.16 g of oxygen. The residue is dissolved in water and precipitated as AgCl . The mass of AgCl (in g ) obtained will be :

(Given : Molar mass of AgCl = 143.5 g mol^-1 )

Options:

Answer:

Solution:

Along with 3 mole $O_{2}$ , i.e., $3 \times 32 g O_{2}$ formed. $AgCl = 2 \times 143.5 g$

$0.16 g O_{2} formed AgCl = \frac{2 \times 143.5}{3 \times 32} \times 0.16 = 0.478 g ≃ 0.48 g$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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