Chemistry - Mole Concept Question with Solution | TestHub

$${\mathrm{H}}_{2(\mathrm{g})}+\frac{1}{2}{\mathrm{O}}_{2(\mathrm{g})}⟶{\mathrm{H}}_2{\mathrm{O}}_{(\ell )}$$ $11.2{\mathrm{dm}}^3$ of ${\mathrm{O}}_2$ gives $18\mathrm{g}$ water at STP $\therefore 9\mathrm{g}$ water is obtained from $\frac{112\times 9}{18}=5.6{\mathrm{dm}}^3$ of ${\mathrm{O}}_2$