Chemistry - Mole Concept Question with Solution | TestHub

${}_5{\mathrm{B}}^{10}+{}_2{\mathrm{He}}^4⟶{}_b^a\mathrm{x}+{}_0{\mathrm{n}}^1$ Balancing atomic numbers, we have $\begin{array}{rl}& 5+2=\mathrm{b}+0\\ & \therefore \mathrm{b}=7\end{array}$ Balancing mass numbers; we have $\begin{array}{rl}& 10+4=a+1\\ & \therefore a=13\end{array}$