Human blood gives rise to an osmotic pressure of approximately 7.65 atm at body temperature, $3 7^{\circ} C$ . Hence , molarity of a glucose solution to have the same osmotic pressure as blood is?
(Take R= 0.0821 L-atm/mol-K)

Question

Human blood gives rise to an osmotic pressure of approximately 7.65 atm at body temperature, $3 7^{\circ} C$ . Hence , molarity of a glucose solution to have the same osmotic pressure as blood is?

(Take R= 0.0821 L-atm/mol-K)

TestHub · Accepted Answer

The osmotic pressure ( Π ) is given by Π = i CRT . For glucose, i = 1 . Given Π = 7.65 atm, R = 0.0821 L atm mol⁻¹ K⁻¹, T = 3 7 ∘ C = 310 K. C = RT Π ​ = 0.0821 L a t mm o l − 1 K − 1 × 310 K 7.65 a t m ​ ≈ 0.30 M . The final answer is 0.30 M ​ .

Chemistry - Liquid Solution Question with Solution | TestHub

Options:

Doubts & Discussion