The Henry law constant for dissolution of a gas in aqueous medium is 3 × 1 0 2 atm . At what partial pressure of the gas (in atm ), the molality of gas in aqueous solution will be 9 5 m .

Question

The Henry law constant for dissolution of a gas in aqueous medium is 3 × 1 0 2 atm . At what partial pressure of the gas (in atm ), the molality of gas in aqueous solution will be 9 5 ​ m .

TestHub · Accepted Answer

p = K H ​ ⋅ n ℓ ​ n g ​ ​ = K H ​ × 1000 m ​ × M solvent ​ p = 3 × 1 0 2 × 9 5 ​ × 1000 1 ​ × 18 = 3 atm

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