When a non-volatile solute is added to the solvent, the vapour pressure of the solvent decreases by 10 mm of Hg . The mole fraction of the solute in the solution is 0.2 . What would be the mole fracti

Question

When a non-volatile solute is added to the solvent, the vapour pressure of the solvent decreases by 10 mm of Hg . The mole fraction of the solute in the solution is 0.2 . What would be the mole fraction of the solvent if decrease in vapour pressure is 20 mm of Hg ?

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Answer:

D

Solution:

$∵ P^{\circ} - P \propto X_{solute} and ∵ 10 \propto 0.2 ∴ 20 \propto 0.4 ∴ X_{solvent} = 1 - X_{solute} = 1 - 0.4 = 0.6$

TestHub · Accepted Answer

​ ∵ P ∘ − P ∝ X solute ​ and ∵ 10 ∝ 0.2 ∴ 20 ∝ 0.4 ∴ X solvent ​ = 1 − X solute ​ = 1 − 0.4 = 0.6 ​

Chemistry - Liquid Solution Question with Solution | TestHub

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