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ChemistryLiquid SolutionRaoult's LawHard2 minPYQ_2021
ChemistryHardnumerical

224 mLofSO2(g)at298 Kand1 atmis passed through100 mLof0.1 M NaOHsolution. The non-volatile solute produced is dissolved in36 gof water. The lowering of vapour pressure of solution (assuming the solution is dilute) (P°H2O=24 mmofHg) isx×10-2 mmofHgthe value ofxis              (Integer answer)

Answer:
18.00
Solution:

Sol 1

SO2+2NaOH  Na2SO3+H2O2240.0821×298=9.2 m mol10 mmol5 mmol(L.R.)(i=3)

P0-Ps=iXsolute P0

=24×3 ×5×10-32

=0.18 = 18×10-3 mm of Hg

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law
2mℹ️ Source: PYQ_2021

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