Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Strong and Weak Acids and BasesMedium2 minQB

ChemistryMediumsingle choice

The pH value of decinormal solution of $NH_{4} OH$ , which is $20%$ ionized is: (Use $lo g 2 = 0.3$ )

Answer:

Solution:

NH₄OH $⇌$ NH₄⁺ + OH⁻

$C (1 - α)$ $C α$ $C α$

$[O H^{-}] = α C = 0.2 \times 0.1 = 0.02$

$pO H = - lo g [2 \times 1 0^{- 2}]$

$pO H = 2 - lo g 2 = 1.7$

$p H = 14 - 1.7 = 12.30$

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Strong and Weak Acids and Bases

⏱ 2mℹ️ Source: QB

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