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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

What is the nature of the resulting solution prepared from $100 m l$ of $0.2 M H_{2} S O_{4}$ added to $100 m l$ of $0.2 M N a O H .$

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Answer:

Solution:

M.eq. of 0.2M $H_{2} S O_{4} = \frac{2 \times 0.2 M}{1000} \times 100 = 0.04$
$M . e q . o f . 2 M N a O H$ $= \frac{0.2}{1000} \times 100 = 0.02$
left $[H^{+}] = 0.04 - 0.02 = 0.02$ .
Total volume $= 200 = \frac{. 02}{200} = . 0001 = 1 0^{- 4} M$
$p H = 4$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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