10 . 0 ml of Na 2 CO 3 solution is titrated against 0 . 2 M HCl solution. The following values were obtained in 5 readings. 4 . 8 ml , 4 . 9 ml , 5 . 0 ml , 5 . 0 ml and 5 . 0 ml Based on these readin

Question

10 . 0 ml of Na 2 CO 3 solution is titrated against 0 . 2 M HCl solution. The following values were obtained in 5 readings. 4 . 8 ml , 4 . 9 ml , 5 . 0 ml , 5 . 0 ml and 5 . 0 ml Based on these readings, and convention of titrimetric estimation of concentration of Na 2 CO 3 solution is ___ mM . (Round off to the Nearest integer)

TestHub · Accepted Answer

Most precise volume of HCl = 5 ml at equivalence point Meq. of Na 2 CO 3 = meq. of HCl Let molarity of Na 2 CO 3 solution = M , then M × 10 × 2 = 0 . 2 × 5 × 1 M = 0 . 05 mol / L = 0 . 05 × 1000 = 50 mM

Chemistry - Ionic Equilibrium Question with Solution | TestHub

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