Chemistry - Ionic Equilibrium Question with Solution | TestHub

pH = 6
$\left[{\mathrm{H}}^{+}\right]=10^{-6}\mathrm{M}$
$100\times 10^{-6}=\mathrm{M}\times 1000$or$\mathrm{M}=10^{-7}$
$\left[{\mathrm{H}}^{+}\right]$already present in water$=10^{-7}$
Total$\left[{\mathrm{H}}^{+}\right]=10^{-7}+10^{-7}=2\times 10^{-7}$
$\mathrm{p}\mathrm{H}=-\mathrm{l}\mathrm{o}\mathrm{g}2\times 10^{-7}=7-\mathrm{l}\mathrm{o}\mathrm{g}2$
$\mathrm{p}\mathrm{H}=7-0.3010=6.7$