Chemistry - Electrochemistry Question with Solution | TestHub

Given electron potential data is-
$\mathrm{C}{\mathrm{l}}_2+2{\mathrm{H}}_2\mathrm{O}\to 2\mathrm{C}\mathrm{l}{\mathrm{O}}^{–}\mathrm{}+4{\mathrm{H}}^{+}+2{\mathrm{e}}^{–};\mathrm{E}°=-1.61$Volt
$\mathrm{C}\mathrm{l}{\mathrm{O}}^{–}+2{\mathrm{H}}_2\mathrm{O}\to \mathrm{C}\mathrm{l}{{\mathrm{O}}_3}^{–}+4{\mathrm{H}}^{+}+4{\mathrm{e}}^{–};\mathrm{E}°=-0.50$Volt
For reaction to be spontaneous${\mathrm{E}}^0$reaction should$+\mathrm{v}\mathrm{e}$, Thus substracting equation$1$from equation$2.$