Calculate emf of the following cell at 2 5 ∘ C if value of E cell ∘ is 4 V (Given RT / F ln 10 = 0.06 ) : M M ( 0.01 M ) 2 + M ( 0.0001 M ) 2 + M

E cell = E cell ∘ − 2 F RT ln 0.0001 0.01 = 4 − 2 F RT ln 1 0 − 4 1 0 − 2 = 4 − 2 F RT ln 1 0 2 = 4 − F RT ln 10 = 4 − 0.06 = 3.94 V

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ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsEasy2 minPYQ_2019

ChemistryEasysingle choice

Calculate emf of the following cell at $2 5^{\circ} C$ if value of $E_{cell}^{\circ}$ is $4 V$ (Given $RT / F ln 10 = 0.06$ ) : $M M_{(0.01 M)}^{2 +} M_{(0.0001 M)}^{2 +} M$

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Answer:

Solution:

$E_{cell} = E_{cell}^{\circ} - \frac{RT}{2 F} ln \frac{0.01}{0.0001} = 4 - \frac{RT}{2 F} ln \frac{1 0 ^{- 2}}{1 0 ^{- 4}} = 4 - \frac{RT}{2 F} ln 1 0^{2} = 4 - \frac{RT}{F} ln 10 = 4 - 0.06 = 3.94 V$

Stream:AIIMSSubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2019

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