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ChemistryElectrochemistryMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

EMF of the following cell is $0.6$ volt.

$A g (s) |A g B r (s)| K B r (0.01 M) | | A g N O_{3} (0.001 M) | A g (s)$

$K_{s p}$ of $A g B r$ is expressed as $1 \times 10^{- x}, x$ is

$[T a k e \frac{2.303 R T}{F} = 0.06 V]$

Answer:

15.00

Solution:

$A g \to A g^{+} (L) + e^{-}$

$A g^{+} (0.001 M) + e^{-} \to A g$

$A g^{+} (0.001 M) \to A g^{+} (L)$

$0.6 = 0 - \frac{0.06}{1} l o g \frac{K_{s p}}{10^{- 2} \times 10^{- 3}}$

$10^{- 10} = \frac{K_{s p}}{10^{- 5}} \Rightarrow K_{s p} = 10^{- 15}$

Stream:NTA_ABHYASSubject:ChemistryTopic:ElectrochemistrySubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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