Chemistry - Electrochemistry Question with Solution | TestHub
ChemistryElectrochemistryFaraday's Law of Electrolysis/Electrolytic CellsMedium2 minQB
ChemistryMediuminteger
A current strength of 96.5 A is passed for 10 s through 1 L of solution of 0.1 M aqueous solution of . What is the pH of the solution ? Use inert electrodes and keep the volume constant at 1 L. Neglect initial acidity and hydrolysis.
Answer:
2
Solution:
At the inert anode, water is oxidized:
Q = 96.5 x 10 = 965 C; Q/F = 965/96500 = 0.01 mol electrons. Thus 0.01 mol H+ is formed in 1 L, so [H+] = 0.01 M and pH = 2.
Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Faraday's Law of Electrolysis/Electrolytic Cells
⏱ 2mℹ️ Source: QB
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