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Chemistry - Coordination Chemistry Question with Solution | TestHub

ChemistryCoordination ChemistryVBT,CFT(complex compound)Medium2 minPYQ_2019

ChemistryMediumsingle choice

The crystal field stabilization energy (CFSE) of $[F e {(H_{2} O)}_{6}] C l_{2}$ and $K_{2} [N i C l_{4}]$ , respectively, are:

Options:

Answer:

Solution:

${[F e {(H_{2} O)}_{6}]}^{2 +}; F e^{+ 2} \Rightarrow 3 d^{6},$ Since $H_{2} O$ is

Weak field ligands,

CFSE $= (4) \times (- 0.4) + 0.6 \times 2 = - 0.4 ∆_{0}$
CFSE $= 4 \times 0.4 + (-) (0.6) \times 4 = - 0.8 ∆_{0}$ and $- 0.8 ∆_{t}$

Stream:JEESubject:ChemistryTopic:Coordination ChemistrySubtopic:VBT,CFT(complex compound)

⏱ 2mℹ️ Source: PYQ_2019

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