Consider the ligands phen, nta³⁻, ox²⁻, dmgH⁻, dien, acac⁻, terpy, en, gly⁻ and imda²⁻. Let X be the number of bidentate ligands, and Y be the total number of donor atoms provided by the remaining lig

Question

Consider the ligands phen, nta³⁻, ox²⁻, dmgH⁻, dien, acac⁻, terpy, en, gly⁻ and imda²⁻. Let X be the number of bidentate ligands, and Y be the total number of donor atoms provided by the remaining ligands when each binds with its maximum denticity (nta³⁻ binds through N and three O atoms; dien, terpy and imda²⁻ are tridentate). Find X + Y.

Answer:

19

Solution:

Bidentate: phen, ox²⁻, dmgH⁻, acac⁻, en, gly⁻, so X = 6. The others are nta³⁻ (4), dien (3), terpy (3) and imda²⁻ (3), so Y = 13. X + Y = 19.

TestHub · Accepted Answer

Bidentate: phen, ox²⁻, dmgH⁻, acac⁻, en, gly⁻, so X = 6. The others are nta³⁻ (4), dien (3), terpy (3) and imda²⁻ (3), so Y = 13. X + Y = 19.

Chemistry - Coordination Chemistry Question with Solution | TestHub

Doubts & Discussion