The complex with highest magnitude of crystal field stabilization energy is______ (Assume crystal field spiltting energy of all complexes are similar)

Question

TestHub · Accepted Answer

Crystal field stabilisation energy of the complex can be calculated as follows,

CFSE = $number of t_{2 g} electrons \times (- 0.4) + number of e_{g} electrons \times (0.6)$

Complex CFSE

${[Ti {({OH}_{2})}_{6}]}^{3 +} ({t_{2 g}}^{1} {e_{g}}^{0})$ $- 0.4 ∆_{0}$

${[Cr {(H_{2} O)}_{6}]}^{3 +} ({t_{2 g}}^{3} {e_{g}}^{0})$ $- 1.2 ∆_{0}$

${[Mn {(H_{2} O)}_{6}]}^{3 +} ({t_{2 g}}^{3} {e_{g}}^{1})$ $- 0.6 ∆_{0}$

${[Fe {(H_{2} O)}_{6}]}^{3 +} ({t_{2 g}}^{3} {e_{g}}^{2})$ $0$

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