Chemistry - Concentration Terms Question with Solution | TestHub

Molality of urea is $4.44\mathrm{m}$, that means 4.44 moles of urea present in $1000\mathrm{gm}$ of water. $\therefore {\mathrm{X}}_{\text{ura }}=\frac{4.44}{4.44+\frac{1000}{18}}$ $=0.0740$ OR $\begin{array}{rl}& 74\times 10^{-3}\\ & X=74\end{array}$