When 35 mL of 0 . 15 M lead nitrate solution is mixed with 20 mL of 0 . 12 M chromic sulphate solution, ____________ × 10 - 5 moles of lead sulphate precipitate out. (Round off to the Nearest Integer)

Question

When 35 mL of 0 . 15 M lead nitrate solution is mixed with 20 mL of 0 . 12 M chromic sulphate solution, ____________ × 10 - 5 moles of lead sulphate precipitate out. (Round off to the Nearest Integer).

TestHub · Accepted Answer

3 Pb NO 3 2 + Cr 2 SO 4 3 → 3 PbSO 4 + 2 Cr NO 3 3 35 ml 20 ml 0 . 15 M 0 . 12 M = 5 . 25 m . mol = 2 . 4 m . mol 5 . 25 m . mol = 5 . 25 × 10 - 3 mol Therefore moles of PbSO 4 formed = 5 . 25 × 10 - 3 = 525 × 10 - 5

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