Chemistry - Concentration Terms Question with Solution | TestHub

$\frac{{\mathrm{MF}}_{\text{solute }}}{{\mathrm{MF}}_{\text{solvent }}}=\frac{{\mathrm{n}}_{\text{solute }}}{{\mathrm{n}}_{\text{solvent }}}=1$$\frac{\frac{W_{\text{solute }}}{{\mathrm{MM}}_{\text{solute }}(\mathrm{x})}}{\frac{{\mathrm{W}}_{\text{solvent }}}{{\mathrm{MM}}_{\text{solvent }}(\mathrm{y})}}=1$

${\mathrm{W}}_{\text{solute }}={\mathrm{W}}_{\text{solvent }}\times \frac{\mathrm{x}}{\mathrm{y}}$

${\left(\%\frac{\mathrm{W}}{\mathrm{W}}\right)}_{\text{solute }}=\frac{{\mathrm{W}}_{\text{solute }}}{{\mathrm{W}}_{\text{solute }}+{\mathrm{W}}_{\text{solvent }}}\times 100$

${\left(\%\frac{\mathrm{W}}{\mathrm{W}}\right)}_{\text{solute }}=\frac{\left({\mathrm{W}}_{\text{solvent }}\frac{\mathrm{x}}{\mathrm{y}}\right)\times 100}{\left({\mathrm{W}}_{\text{solvent }}\frac{\mathrm{x}}{\mathrm{y}}+{\mathrm{W}}_{\text{solvent }}\right)}$

${\left(\%\frac{W}{W}\right)}_{\text{solute }}=\frac{\left(\frac{x}{y}\right)}{\left(\frac{x}{y}+1\right)}\times 100=\frac{x}{x+y}\times 100$

${\left(\%\frac{\mathrm{W}}{\mathrm{W}}\right)}_{\mathrm{W}\text{ solvent }}=\frac{{\mathrm{W}}_{\text{solvent }}}{{\mathrm{W}}_{\text{solute }}+{\mathrm{W}}_{\text{solvent }}}\times 100$

$=\frac{W}{W\frac{x}{y}+W}\times 100$$=\frac{1}{\frac{x}{y}+1}\times 100$$=\frac{y}{x+y}\times 100$

$\mathrm{Now}{\left(\%\frac{W}{W}\right)}_{\text{solute }}=\left(\frac{x}{x+y}\times 100\right)\times \frac{y}{y}$

$\begin{array}{rlr}& =\frac{x}{y}\left(\frac{y}{x+y}\times 100\right)& =\frac{x}{y}mass\end{array}\%\circ fsolvent$