Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

ChemistryEasysingle choice

Rate constant of two reactions are given below. Indentifying their order of reaction.
$(i) k = 6.3 \times 1 0^{- 2} L m o l^{- 1} s^{- 1}$
$(i i) k = 2.8 \times 1 0^{- 4} s^{- 1}$

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Answer:

Solution:

For second order, units of rate constant
$= \frac{m o l L^{- 1}}{s} \times \frac{1}{(m o l L^{- 1})^{2}}$
$= m o l^{- 1} L s^{- 1}$
For first order, units of rate constant $= \frac{m o l L^{- 1}}{s} \times \frac{1}{m o l L^{- 1}} = s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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