Chemistry - Chemical Kinetics Question with Solution | TestHub

The acid is a catalyst, so $\left[{\mathrm{H}}^{+}\right]$ stays at 0.05 M.

Pseudo first order: $k^{\prime }=0.02\times 0.05=1\times 10^{-3}\mathrm{mi}{\mathrm{n}}^{-1}$.

$t_{1/2}=\frac{0.693}{10^{-3}}=693\min$.

(The initial sucrose concentration does not affect the half-life.)

Answer: (A).