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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

ChemistryEasysingle choice

In the following reaction,
$2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)$
The rate of formation of $S O_{3}$ is 100 g $m i n^{- 1}$ . Hence, the rate of disappearance of $C O_{2}$ is

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Answer:

Solution:

In the reaction
$2 {SO}_{2} (g) + \underset{\underset{32 g}{1 mol}}{O_{2} (g)} \to \underset{\underset{160 g}{2 mol}}{2 {SO}_{3} (g)}$
Hence, 160 g of $S O_{3}$ is formed by 32 g of $O_{2}$
So 100 g of $S O_{3}$ will be formed $= \frac{32}{160} \times 100 =$ 20 g of $O_{2}$
So rate of disappearance of $O_{2} = 20$ g $m i n^{- 1}$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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