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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsFirst Order ReactionsEasy2 minQB

ChemistryEasysingle choice

The half-life of iodine-131 is 8.0 days. If 64 mg of iodine-131 is released in an accident, calculate the mass (in mg) of the nuclide that remains after 20 days.

Options:

Answer:

Solution:

$m = 64 \times 2^{- 20/8} = 64 \times 2^{- 2.5} = 64 \times 0.1768 = 11.3$ mg.

Answer: (A).

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: QB

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