Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumLe-Chatelier's PrincipleMedium2 minQB

ChemistryMediummultiple choice

For reaction $C (s) + CO_{2} (g) ⇌ 2 CO (g)$

Options:(select one or more)

Answer:

A, B

Solution:

$K_{p} = \frac{( p _{CO} ) ^{2}}{p _{C O_{2}}}$ at equilibrium.

When more CO₂ is added, $Q_{p} < K_{c}$ . To reach equilibrium, the system moves in the forward direction. Hence, choice (a) is correct.

When more CO is added, $Q_{p} > K_{p}$ . To reach equilibrium, the system moves in the backward direction. So, choice (b) is also correct.

Since the concentration of solids is constant, changing the amount of carbon(s) does not change its concentration. Hence, adding carbon does not affect the equilibrium. Thus, option (c) is incorrect, whereas option (d) is correct.

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Le-Chatelier's Principle

⏱ 2mℹ️ Source: QB

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