Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumProblems involving KpHard2 minQB
ChemistryHardmatching list

Column I

Column II

\begin{gathered}{}\text{i)}\text{ }\text{50%}\text{ }\text{dissociation}\text{ }\text{of}\text{ }\text{CaCO}_{\text{3}}\end{gathered}

\begin{gathered}{}\text{ii)}\text{ }\text{100%}\text{ }\text{dissociation}\text{ }\text{of}\text{ }\text{CaCO}_{\text{3}}\end{gathered}

 

Options:

Answer:
C
Solution:

\begin{gathered}{}\text{At}\text{ }\text{equilibrium}\text{ }\text{p}_{\text{CO2}}\text{ }\text{=}\text{ }\text{K}_{\text{p}}\text{ }\text{=}\text{ }\text{2.463}\text{ }\text{atm,}\text{ }\text{so}\text{ }\text{n}_{\text{CO2}}\text{ }\text{=}\text{ }\text{pV/(RT)}\text{ }\text{=}\text{ }\text{(2.463}\text{ }\times\text{ }\\{}\text{15.0)/(0.0821}\text{ }\times\text{ }\text{900)}\text{ }\text{=}\text{ }\text{0.50}\text{ }\text{mol}\text{ }\text{0.50}\text{ }\text{mol}\text{ }\text{of}\text{ }\text{CO}_{\text{2}}\text{ }\text{needs}\text{ }\text{0.50}\text{ }\text{mol}\text{ }\text{of}\text{ }\text{CaCO}_{\text{3}}\text{ }\text{=}\text{ }\text{50}\text{ }\text{g}\text{ }\\{}\text{to}\text{ }\text{dissociate}\\{}\text{P:}\text{ }\text{100}\text{ }\text{g}\text{ }\text{is}\text{ }\text{more}\text{ }\text{than}\text{ }\text{50}\text{ }\text{g,}\text{ }\text{so}\text{ }\text{only}\text{ }\text{50}\text{ }\text{g}\text{ }\text{dissociates,}\text{ }\text{i.e.}\text{ }\text{50%}\text{ }\text{dissociation}\text{ }\\{}\text{(i);}\text{ }\text{solid}\text{ }\text{CaCO}_{\text{3}}\text{ }\text{remains,}\text{ }\text{so}\text{ }\text{adding}\text{ }\text{a}\text{ }\text{little}\text{ }\text{CO}_{\text{2}}\text{ }\text{shifts}\text{ }\text{the}\text{ }\text{equilibrium}\text{ }\\{}\text{backward}\text{ }\text{(iii)}\\{}\text{Q:}\text{ }\text{exactly}\text{ }\text{50}\text{ }\text{g}\text{ }\text{dissociates}\text{ }\text{fully,}\text{ }\text{100%}\text{ }\text{dissociation}\text{ }\text{(ii);}\text{ }\text{with}\text{ }\text{no}\text{ }\text{solid}\text{ }\text{left,}\text{ }\\{}\text{adding}\text{ }\text{a}\text{ }\text{small}\text{ }\text{amount}\text{ }\text{of}\text{ }\text{CO}_{\text{2}}\text{ }\text{can}\text{ }\text{push}\text{ }\text{the}\text{ }\text{reaction}\text{ }\text{backward}\text{ }\text{(iii)}\\{}\text{R:}\text{ }\text{25}\text{ }\text{g}\text{ }\text{dissociates}\text{ }\text{fully}\text{ }\text{(ii);}\text{ }\text{with}\text{ }\text{the}\text{ }\text{solid}\text{ }\text{exhausted,}\text{ }\text{adding}\text{ }\text{10}\text{ }\text{g}\text{ }\text{more}\text{ }\text{CaCO}_{\text{3}}\text{ }\\{}\text{lets}\text{ }\text{more}\text{ }\text{dissociation}\text{ }\text{occur,}\text{ }\text{increasing}\text{ }\text{moles}\text{ }\text{of}\text{ }\text{CO}_{\text{2}}\text{ }\text{(iv)}\\{}\text{The}\text{ }\text{correct}\text{ }\text{mapping}\text{ }\text{is}\text{ }\text{option}\text{ }\text{(c).}\end{gathered}

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp
⏱ 2mℹ️ Source: QB

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