Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KcMedium2 minQB
ChemistryMediumsingle choice
The equilibrium constant for the reaction CO(g) + H2O(g) ⇌ CO2(g) + H2(g) is 5.0 at 800 K. In a 4.0 L vessel, 90 g of water gas [equimolar mixture of CO(g) and H2(g)] and 72 g of steam are initially taken. The equilibrium concentration of H2(g) is
Options:
Answer:
A
Solution:
Mean molar mass of the equimolar mixture = (28 + 2)/2 = 15 g/mol, so moles = 90/15 = 6, that is 3 mol CO and 3 mol H2 Steam = 72/18 = 4 mol
Let x mol of CO react: CO = 3 - x, H2O = 4 - x, CO2 = x, H2 = 3 + x
Δ ng = 0, so volume cancels: x(3+x)/[(3-x)(4-x)] = 5
x2 + 3x = 60 - 35x + 5x2 gives 2x2 - 19x + 30 = 0
x = (19 - 11)/4 = 2 (the root 7.5 is not possible)
H2 = 5 mol in 4.0 L, so [H2] = 1.25 M
This is option (a).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB
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